If the numerator of a fraction is increased by 40% and the denominator is doubled the new fraction obtained is $$\frac{7}{16}$$ . What was the original fraction ?

If the numerator of a fraction is increased by 40% and the denominator is doubled the new fraction obtained is $$\frac{7}{16}$$ . What was the original fraction ?
1). 5/8
2). 3/8
3). 7/8
4). Cannot be determined

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Guest · Answer 1 · 2019-04-09 22:50:32

Solution

Let the original fraction be $\frac{p}{q}$
The numerator when increased by 40% becomes = 1.4p
The denominator when doubled becomes = 2q
Hence, $\frac{1.4p}{2q} = \frac{7}{16}$
$\frac{p}{q} = \frac{10}{16} = \frac{5}{8}$

Guest · Answer 2 · 2019-05-08 13:01:22

Solution

Let the original fraction be $\frac{p}{q}$
The numerator when increased by 40% becomes = 1.4p
The denominator when doubled becomes = 2q
Hence, $\frac{1.4p}{2q} = \frac{7}{16}$
$\frac{p}{q} = \frac{10}{16} = \frac{5}{8}$

If the numerator of a fraction is increased by 40% and the denominator is doubled the new fraction obtained is $$\frac{7}{16}$$ . What was the original fraction ?

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