18 men can complete a project in 30 days and 16 women can complete the same project in 36 days. 15 men start working and after 9 days they are replaced by 18 women. In how many days will 18 women complete the remaining work ?

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18 men can complete a project in 30 days and 16 women can complete the same project in 36 days. 15 men start working and after 9 days they are replaced by 18 women. In how many days will 18 women complete the remaining work ?

Asked on 2018-06-24 10:31:33 by Guest | Votes 0 | Views: 67 | Tags: ibps | ibps po | ibps po 2015 | time and work | quantitative aptitude | Add Bounty

18 men can complete a project in 30 days and 16 women can complete the same project in 36 days. 15 men start working and after 9 days they are replaced by 18 women. In how many days will 18 women complete the remaining work ?
1). 20
2). 30
3). 26
4). 28

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2 answers

1 vote

Answered by Guest on 2019-04-10 15:14:16 | Votes 1 | #

Solution

$\frac{M1D1}{W1}$ = $\frac{M2D2}{W2}$

W1=W2 = Q

$\frac{18Mx30}{Q}$ = $\frac{16Wx36}{Q}$

M = $\frac{32}{30}$W ....(1)

Let the days required by 18 women to complete the remaining work = y days

so $\frac{(15Mx9)+(18W x y)}{Q}$ = $\frac{16Wx36}{Q}$ ......(2)

using equation 1 and 2

$\frac{(16Wx9)+(18W x y)}{Q}$ = $\frac{16Wx36}{Q}$

144W + 18Wy = 576W

18Wy = 432 W

y = 24 days

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0 vote

Answered by Guest on 2019-05-11 06:57:33 | Votes 0 | #

Solution

$\frac{M1D1}{W1}$ = $\frac{M2D2}{W2}$

W1=W2 = Q

$\frac{18Mx30}{Q}$ = $\frac{16Wx36}{Q}$

M = $\frac{32}{30}$W ....(1)

Let the days required by 18 women to complete the remaining work = y days

so $\frac{(15Mx9)+(18W x y)}{Q}$ = $\frac{16Wx36}{Q}$ ......(2)

using equation 1 and 2

$\frac{(16Wx9)+(18W x y)}{Q}$ = $\frac{16Wx36}{Q}$

144W + 18Wy = 576W

18Wy = 432 W

y = 24 days

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