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The largest number that divides 43, 91 and 183 and leaves the same remainder in each case is

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The largest number that divides 43, 91 and 183 and leaves the same remainder in each case is
1). 16
2). 8
3). 9
4). 13

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Solution

The required number is the HCF of (91 - 43), (183 - 91) and (183 - 43) = HCF of (48, 92, 140) = 4

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