The number obtained by interchanging the digits of a two-digit number is less than the original number by 63 If the sum of the digits of the number is 11, what is the original number ?

The number obtained by interchanging the digits of a two-digit number is less than the original number by 63 If the sum of the digits of the number is 11, what is the original number ?
1). 29
2). 92
3). 74
4). Cannot be determined

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Guest · Answer 1 · 2019-04-09 10:37:01

Solution

Let units place digit be x and tens place digit be y.
Original number = 10y + x
Number obtained on interchanging the digits = 10x +y
By given conditond,
x+y = 11
10x +y = 10y +x - 63
9y - 9x = 63
y - x = 7
Solving the linear equations we get,
y=9 and x=2

Original number is 92 i.e option B.

Guest · Answer 2 · 2019-05-03 17:38:10

Solution

Let units place digit be x and tens place digit be y.
Original number = 10y + x
Number obtained on interchanging the digits = 10x +y
By given conditond,
x+y = 11
10x +y = 10y +x - 63
9y - 9x = 63
y - x = 7
Solving the linear equations we get,
y=9 and x=2

Original number is 92 i.e option B.

The number obtained by interchanging the digits of a two-digit number is less than the original number by 63 If the sum of the digits of the number is 11, what is the original number ?

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