The difference of two two-digit numbers is 18. Four times the second number is 18 more than thrice the first number. Find sum of both numbers.
1). 162
2). 165
3). 89
4). 48
Let the numbers be $x$ and $y$
=> $x - y = 18$ -----------------Eqn(1)
and $4y - 3x = 18$
Using equation (1), we get :
=> $4(x - 18) - 3x = 18$
=> $4x - 72 - 3x = 18$
=> $x = 18 + 72 = 90$
=> $y = 90 - 18 = 72$
$\therefore$ Sum of numbers = $90 + 72 = 162$
Let the numbers be $x$ and $y$
=> $x - y = 18$ -----------------Eqn(1)
and $4y - 3x = 18$
Using equation (1), we get :
=> $4(x - 18) - 3x = 18$
=> $4x - 72 - 3x = 18$
=> $x = 18 + 72 = 90$
=> $y = 90 - 18 = 72$
$\therefore$ Sum of numbers = $90 + 72 = 162$