When one? sixth of a number x, is added to 117, it becomes equal to y?. If one ?fifth of y is equal to 2.2, what is the value of x ?
1). 24
2). 22
3). 28
4). 30
Given : $\frac{1}{5} \times y = 2.2$
=> $y = 2.2 \times 5 = 11$
Acc to ques,
=> $(\frac{1}{6} \times x) + 117 = (y)^2$
=> $\frac{x}{6} + 117 = (11)^2 = 121$
=> $\frac{x}{6} = 121 - 117 = 4$
=> $x = 4 \times 6 = 24$
Given : $\frac{1}{5} \times y = 2.2$
=> $y = 2.2 \times 5 = 11$
Acc to ques,
=> $(\frac{1}{6} \times x) + 117 = (y)^2$
=> $\frac{x}{6} + 117 = (11)^2 = 121$
=> $\frac{x}{6} = 121 - 117 = 4$
=> $x = 4 \times 6 = 24$
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