The denominator of a fraction is 2 more than thrice it?s numerator.If the numerator as well as denominator are increased by one,the fraction becomes ? .what was that the original fraction?
1). 2/8
2). 3/11
3). 4/14
4). 5/17
Let the numerator = $x$
=> Denominator = $(3x+2)$
Fraction = $\frac{x}{3x+2}$
If the numerator as well as denominator are increased by one
=> $\frac{x+1}{3x+2+1}=\frac{1}{3}$
=> $\frac{x+1}{3x+3}=\frac{1}{3}$
=> $3x+3=3x+3$
It cannot be solved, thus $x$ can take any value and the fraction can be 2/8 , 3/11 , 4/14 ,....
=> Ans - (E)
Let the numerator = $x$
=> Denominator = $(3x+2)$
Fraction = $\frac{x}{3x+2}$
If the numerator as well as denominator are increased by one
=> $\frac{x+1}{3x+2+1}=\frac{1}{3}$
=> $\frac{x+1}{3x+3}=\frac{1}{3}$
=> $3x+3=3x+3$
It cannot be solved, thus $x$ can take any value and the fraction can be 2/8 , 3/11 , 4/14 ,....
=> Ans - (E)