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20 vote

A shopkeeper sold 8 chairs at a profit of 20% and 6 chairs at a profit of 10%. Had he sold all the 14 chairs at a profit of 12%, his profit would have been reduced by 442. What is the cost price of each chair? (cost of each chair is same)

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A shopkeeper sold 8 chairs at a profit of 20% and 6 chairs at a profit of 10%. Had he sold all the 14 chairs at a profit of 12%, his profit would have been reduced by 442. What is the cost price of each chair? (cost of each chair is same)
1). Rs. 750
2). Rs. 775
3). Rs. 825
4). Rs. 850


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2 answers

29 vote
Answered by on | Votes 29 |
Solution

Let C.P. of each chair = $100x$

Case 1 : 8 chairs sold at 20% profit

=> S.P. of 8 chairs = $8 \times \frac{120}{100} \times 100x = 960x$

6 chairs sold at 10% profit

=> S.P. of 6 chairs = $6 \times \frac{110}{100} \times 100x = 660x$

$\therefore$ Total S.P. of 14 chairs = $960x + 660x = 1620x$

Case 2 : 14 chairs sold at 12% profit

=> S.P. of 14 chairs = $14 \times \frac{112}{100} \times 100x = 1568x$

Acc. to ques,

=> $1620x - 1568x = 442$

=> $52x = 442$

=> $xx = \frac{442}{52} = 8.5$

$\therefore$ C.P. of 1 chair = $100 \times 8.5$ = Rs. 850

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3 vote
Answered by on | Votes 3 |
Solution

Let C.P. of each chair = $100x$

Case 1 : 8 chairs sold at 20% profit

=> S.P. of 8 chairs = $8 \times \frac{120}{100} \times 100x = 960x$

6 chairs sold at 10% profit

=> S.P. of 6 chairs = $6 \times \frac{110}{100} \times 100x = 660x$

$\therefore$ Total S.P. of 14 chairs = $960x + 660x = 1620x$

Case 2 : 14 chairs sold at 12% profit

=> S.P. of 14 chairs = $14 \times \frac{112}{100} \times 100x = 1568x$

Acc. to ques,

=> $1620x - 1568x = 442$

=> $52x = 442$

=> $xx = \frac{442}{52} = 8.5$

$\therefore$ C.P. of 1 chair = $100 \times 8.5$ = Rs. 850




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