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31 vote

The sum of allowances received by Riddhi and Siddhi together was Rs. 3,800/?. Riddhi and Siddhi both paid 2/8th of their respective allowances as their tuition fees. If the tuition fees paid by Siddhi was more than that paid by Riddhi, by Rs. 80/?, how much was Riddhi?s allowances ?

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The sum of allowances received by Riddhi and Siddhi together was Rs. 3,800/?. Riddhi and Siddhi both paid 2/8th of their respective allowances as their tuition fees. If the tuition fees paid by Siddhi was more than that paid by Riddhi, by Rs. 80/?, how much was Riddhi?s allowances ?
1). Rs. 1,800/­
2). Rs. 1,740/­
3). Rs. 1,640/­
4). Rs. 1,840/­


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2 answers

36 vote
Answered by on | Votes 36 |
Solution

Let Riddhi's allowance = Rs. $8x$

=> Siddhi's allowance = Rs. $(3800 - 8x)$

Allowance paid as tuition fees by

Riddhi = $\frac{2}{8} \times 8x = 2x$

Siddhi = $\frac{2}{8} \times (3800 - 8x) = 950 - 2x$

Acc to ques,

=> $(950 - 2x) - (2x) = 80$

=> $950 - 4x = 80$

=> $4x = 950 - 80 = 870$

=> $x = \frac{870}{4}$

$\therefore$ Riddhi's allowance = $8 \times \frac{870}{4}$

= $2 \times 870$ = Rs. $1,740$

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2 vote
Answered by on | Votes 2 |
Solution

Let Riddhi's allowance = Rs. $8x$

=> Siddhi's allowance = Rs. $(3800 - 8x)$

Allowance paid as tuition fees by

Riddhi = $\frac{2}{8} \times 8x = 2x$

Siddhi = $\frac{2}{8} \times (3800 - 8x) = 950 - 2x$

Acc to ques,

=> $(950 - 2x) - (2x) = 80$

=> $950 - 4x = 80$

=> $4x = 950 - 80 = 870$

=> $x = \frac{870}{4}$

$\therefore$ Riddhi's allowance = $8 \times \frac{870}{4}$

= $2 \times 870$ = Rs. $1,740$




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