The present population of a city P is thrice the present population of city Q. Two years hence, the population of city Q will be 18513. If the rate of growth of population of city Q is 10% per annum, what is the present population of city P ?
1). 48500
2). 45500
3). 49500
4). 45900
Let the present population of city Q = $x$
=> $x (1 + \frac{10}{100})^2 = 18513$
=> $x \times \frac{121}{100} = 18513$
=> $x = 15300$
$\therefore$ Present population of city P = 15300 * 3 = 45900
Let the present population of city Q = $x$
=> $x (1 + \frac{10}{100})^2 = 18513$
=> $x \times \frac{121}{100} = 18513$
=> $x = 15300$
$\therefore$ Present population of city P = 15300 * 3 = 45900
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