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Train A, whose length is 328 metre can cross a 354 metre long platform in 11 seconds. Train B can cross the same platform in 12 seconds. If the speed of train? B is 7/8th of the speed of train?A, what is the length of train?B ? (in m)

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Train A, whose length is 328 metre can cross a 354 metre long platform in 11 seconds. Train B can cross the same platform in 12 seconds. If the speed of train? B is 7/8th of the speed of train?A, what is the length of train?B ? (in m)
1). 321
2). 303
3). 297
4). 273


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2 answers

5 vote
Answered by on | Votes 5 |
Solution

Speed = $\frac{\textrm{Length of train + Length of platform}}{Time}$

=> Speed of train A = $\frac{328 + 354}{11}$

= $\frac{682}{11} = 62$ m/s

=> Speed of train B = $\frac{7}{8} \times 62$

= $\frac{217}{4}$ m/s

Let length of train B = $l$

=> $\frac{l + 354}{12} = \frac{217}{4}$

=> $l + 354 = \frac{217}{4} \times 12$

=> $l + 354 = 217 \times 3 = 651$

=> $l = 651 - 354 = 297$ metre

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0 vote
Answered by on | Votes 0 |
Solution

Speed = $\frac{\textrm{Length of train + Length of platform}}{Time}$

=> Speed of train A = $\frac{328 + 354}{11}$

= $\frac{682}{11} = 62$ m/s

=> Speed of train B = $\frac{7}{8} \times 62$

= $\frac{217}{4}$ m/s

Let length of train B = $l$

=> $\frac{l + 354}{12} = \frac{217}{4}$

=> $l + 354 = \frac{217}{4} \times 12$

=> $l + 354 = 217 \times 3 = 651$

=> $l = 651 - 354 = 297$ metre




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