Train A, whose length is 328 metre can cross a 354 metre long platform in 11 seconds. Train B can cross the same platform in 12 seconds. If the speed of train? B is 7/8th of the speed of train?A, what is the length of train?B ? (in m)
1). 321
2). 303
3). 297
4). 273
Speed = $\frac{\textrm{Length of train + Length of platform}}{Time}$
=> Speed of train A = $\frac{328 + 354}{11}$
= $\frac{682}{11} = 62$ m/s
=> Speed of train B = $\frac{7}{8} \times 62$
= $\frac{217}{4}$ m/s
Let length of train B = $l$
=> $\frac{l + 354}{12} = \frac{217}{4}$
=> $l + 354 = \frac{217}{4} \times 12$
=> $l + 354 = 217 \times 3 = 651$
=> $l = 651 - 354 = 297$ metre
Speed = $\frac{\textrm{Length of train + Length of platform}}{Time}$
=> Speed of train A = $\frac{328 + 354}{11}$
= $\frac{682}{11} = 62$ m/s
=> Speed of train B = $\frac{7}{8} \times 62$
= $\frac{217}{4}$ m/s
Let length of train B = $l$
=> $\frac{l + 354}{12} = \frac{217}{4}$
=> $l + 354 = \frac{217}{4} \times 12$
=> $l + 354 = 217 \times 3 = 651$
=> $l = 651 - 354 = 297$ metre
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