35 vote
In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 10%
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In 1 kg of a mixture of sand and iron, 20% is iron .How such sand should be added so that the proportion of iron becomes 10%
1). 1 kg
2). 200gm
3). 800 gm
4). 1.8 kg
3 answers
37 vote
Solution
Total mixture of sand and iron = 1 kg
Quantity of iron = $\frac{20}{100} \times 1 = 0.2$ kg
Let $x$ kg of sand should be added, thus total iron in the mixture
=> $0.2=\frac{10}{100} \times (x+1)$
=> $2=x+1$
=> $x=2-1=1$ kg
=> Ans - (A)
1 vote
Solution
Total mixture of sand and iron = 1 kg
Quantity of iron = $\frac{20}{100} \times 1 = 0.2$ kg
Let $x$ kg of sand should be added, thus total iron in the mixture
=> $0.2=\frac{10}{100} \times (x+1)$
=> $2=x+1$
=> $x=2-1=1$ kg
=> Ans - (A)