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What should come in place of question mark (?) in the following questions?

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What should come in place of question mark (?) in the following questions?


$$\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}=?$$
1). $$\frac{40}{121}$$
2). $$\frac{36}{171}$$
3). $$\frac{14}{171}$$
4). $$\frac{22}{171}$$


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2 answers

0 vote
Answered by on | Votes 0 |
Solution

We need to find the value of $\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}$

Let us first calculate the numerator, $34 \times 4 - 12 \times 8 = 136 - 96 = 40$
The denominator equals $6^2 + \sqrt{196} +11^2 = 36 +14 +121 = 171$

Hence, the fraction equals $\frac{40}{171}$

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3 vote
Answered by on | Votes 3 |
Solution

We need to find the value of $\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}$

Let us first calculate the numerator, $34 \times 4 - 12 \times 8 = 136 - 96 = 40$
The denominator equals $6^2 + \sqrt{196} +11^2 = 36 +14 +121 = 171$

Hence, the fraction equals $\frac{40}{171}$




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