What should come in place of question mark (?) in the following questions?
We need to find the value of $\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}$
Let us first calculate the numerator, $34 \times 4 - 12 \times 8 = 136 - 96 = 40$
The denominator equals $6^2 + \sqrt{196} +11^2 = 36 +14 +121 = 171$
Hence, the fraction equals $\frac{40}{171}$
We need to find the value of $\frac{34 \times 4-12 \times 8}{6^{2}+\sqrt{196}+(11)^{2}}$
Let us first calculate the numerator, $34 \times 4 - 12 \times 8 = 136 - 96 = 40$
The denominator equals $6^2 + \sqrt{196} +11^2 = 36 +14 +121 = 171$
Hence, the fraction equals $\frac{40}{171}$