32% of 500 + 162% of 50 = ?1). 2312). 2453). 2374). 247
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32% of 500 = $\frac{32}{100}\times500$ = 160
162% of 50 = $\frac{162}{100}\times50$ = 81
160 + 81 = 241
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1. If ‘a’ exceeds ‘b’ by y%, then which of the following is correct?
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