$$2\frac{1}{9} \times 1\frac{2}{19} \div 2\frac{1}{3} = ? - 1\frac{1}{2}$$

$$2\frac{1}{9} \times 1\frac{2}{19} \div 2\frac{1}{3} = ? - 1\frac{1}{2}$$
1). $$3\frac{1}{2}$$
2). $$1\frac{1}{4}$$
3). $$2\frac{1}{2}$$
4). $$2\frac{1}{4}$$

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Guest · Answer 1 · 2019-05-15 13:12:27

Solution

Let the unknown be $x$.
$2\frac{1}{9} = \frac{19}{9}$ , $1\frac{2}{19}$ = $\frac{21}{19}$ , $2\frac{1}{3}$ =$ \frac{7}{3}$ , $1\frac{1}{2}$=$\frac{3}{2}$

$\frac{21}{19} \div \frac{7}{3}$ =$ \frac{9}{19}$

$\frac{19}{9} \times \frac{9}{19}$ =$1$
$1 = x - \frac{3}{2}$
$x = 1 + \frac{3}{2}$
$x=\frac{5}{2} = 2\frac{1}{2}$
Hence Option C is the correct answer.

$$2\frac{1}{9} \times 1\frac{2}{19} \div 2\frac{1}{3} = ? - 1\frac{1}{2}$$

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