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If $\omega$ is a complex cube root of unity, then the value of $(1-\omega)^{6}$ is:

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If $\omega$ is a complex cube root of unity, then the value of $(1-\omega)^{6}$ is:
1). -9
2). -27
3). 0
4). 6


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1 answers

3 vote
Answered by on | Votes 3 |
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