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Let a and b be the roots of the equation Let c and d $x^{2}+px+1=0$ be the roots of the equation $x^{2}+qx+1=0$, Then the value of (a-c)(b-c)(a + d)(b + d) is equal to:

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Let a and b be the roots of the equation Let c and d $x^{2}+px+1=0$ be the roots of the equation $x^{2}+qx+1=0$,
Then the value of (a-c)(b-c)(a + d)(b + d) is equal to:
1). $-p^{2}+q^{2}$
2). $p^{2}-q^{2}$
3). $-p^{2}-q^{2}$
4). $p^{2}+q^{2}$


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