A number is increased by x%; to get back to the original number, it is to be reduced by
1). x%
2). $\frac{100x}{100+x}$%
3). $\frac{10x}{100+x}$%
4). $\frac{x}{100+x}$%
.Initial value -> increasing value
= $\frac{p\times x}{100}$ -> increased value--> P +$\frac{p x}{100}$
= p [$\frac{100+ x}{100}$]
= Required answer
x = $\frac{ x}{100+x}\times100$