0 vote
tanθ + cotθ is
tanθ + cotθ is
1). 1
2). tanθ
3). cosecθ cotθ
4). secθcosecθ
1 answers
1 vote
$(\begin{array}{l}
\Rightarrow {\rm{\;}}\tan {\rm{\theta \;}} + {\rm{\;}}\cot {\rm{\theta }} = {\rm{\;}}\left( {\frac{{{\rm{sin\theta }}}}{{{\rm{cos\theta }}}}} \right){\rm{\;}} + {\rm{\;}}\left( {\frac{{{\rm{cos\theta }}}}{{{\rm{sin\theta }}}}} \right)\\
= \frac{{{{\sin }^2}{\rm{\theta \;}} + {\rm{\;}}{{\cos }^2}{\rm{\theta }}}}{{{\rm{sin\theta cos\theta }}}} = {\rm{\;}}\frac{1}{{{\rm{sin\theta cos\theta }}}} = {\rm{\;sec\theta cosec\theta }}
\end{array})$