If 1 + 10 + 102 + …….. upto n terms \(= \frac{{{{10}^n} - 1}}{9}\), then the sum of the series 3 + 33 + 333 + ………. Upto n term is

If 1 + 10 + 10² + …….. upto n terms \(= \frac{{{{10}^n} - 1}}{9}\), then the sum of the series 3 + 33 + 333 + ………. Upto n term is
1). \(\frac{3}{9}\left( {{{10}^n} - 1} \right) - \frac{{3n}}{9}\)
2). \(\frac{30}{{81}}\left( {{{10}^n} - 1} \right) - \frac{{3n}}{90}\)
3).  30/81 (10ⁿ – 1) – (3n/9)
4). \(\frac{{30}}{9}\left( {{{10}^n} - 1} \right) - \frac{{3n}}{9}\)

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