If the sum of two numbers is 66 and the H.C.F and L.C.M of the numbers are 6 and 120 respectively, then the sum of the reciprocals of numbers is equal to∶
1). 11/120
2). 21/120
3). 15/130
4). 55/120
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Let the numbers are x and y
Then, x + y = 66
We know that,
LCM × HCF = Product of two numbers
⇒ xy = 6 × 120 = 720
∴ required sum $(= \frac{1}{{\rm{x}}} + \frac{1}{{\rm{y}}} = \frac{{\left( {{\rm{x\;}} + {\rm{\;y}}} \right)}}{{{\rm{xy}}}} = \frac{{66}}{{720}} = \frac{{11}}{{120}})$1. If the number 4 - 8 + 5 - 4 + 7 - * + 9 is divisible by 11, then the missing digit (*) is
2. A number when divided by 72 leaves remainder 10. What will be the same number is divided by 9?
3. How many numbers less than 1000 are multiples of both 10 and 17?
4. 450% of a number is 4725. What is 82% of that number ?
5. 2/11 of 3/7 of 8/13 of 12012 = ?
6. In how many different ways can be the letters of the word PENCIL be arranged among themselves ?