The sum of two numbers is 24 and their product is 143. The sum of their squares is
1). 296
2). 295
3). 290
4). 228
Formula to be used :
(a + b)2 = a2 + b2 + 2ab -------------1
Let the numbers be ‘a’ and ‘b’.
Given, sum of the numbers is 24
∴ a + b = 24
Also given, product of numbers is 143
∴ ab = 143
Substituting the above values in equation 1 we get
⇒ 242 = a2 + b2 + 2 × 143
⇒ 576 = a2 + b2 + 286
⇒ a2 + b2 = 2901. If (8x - 4) = (3x + 6), then the numerical value of $(x + 1)^{3}$ is
2. If \(a - b = \sqrt 2 \;and\;a + b = \sqrt 3 \), then the value of 4ab (a2 + b2) is
4. If [x – (1/x)] = 2, then what is the value of [x + 1/x]?
5. If the orthocentre and the centroid of a triangle are the same, then the triangle is:
6. If$ 5^{x} $= $30^{-y}$ = $6^{z}$, then what is the value of $\frac{(xy + yz + zx)}{xyz}$?