B is 50% of A and C is 16.67% of B and the sum of all three numbers is 38. Find the smallest number.
1). 1
2). 4
3). 6
4). 2
Let A = a so B = 50% of a = a/2 and C = 16.67% of a/2 = 1/6 × a/2 = a/12
A + B + C = a + a/2 + a/12 = 38
⇒ 19a/12 = 38
⇒ a = 24
∴ Smallest number, C = a/12 = 24/12 = 2