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A man with $\frac{3}{5}$ of his usual speed reaches the destination $2\frac{1}{2}$ hours late. Find his usual time to reach the destination.
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A man with $\frac{3}{5}$ of his usual speed reaches the destination $2\frac{1}{2}$ hours late. Find his usual time to reach the destination.
1). 4 hr.
2). 3 hr.
3). $3\frac{3}{4}$ hr.
4). $4\frac{1}{2}$ hr.
3 answers
2 vote
$\frac{3}{5}$ of usual speed will take
$\frac{5}{3}$ of usual time.
[Q time & speed are inversely
proportional]
so that,
$\frac{5}{3}$ of usual time
= usual time +$\frac{5}{2}$
=>$\frac{2}{3}$ of usual time =$\frac{5}{2}$
=> usual time
=$\frac{5}{2}\times\frac{3}{2}=\frac{15}{4}=3\frac{3}{4}$