0 vote
B is 50% more efficient than A & 20% more efficient than C. If B can complete a work in 20 days, how many days will A & C together take to compete the same work.
B is 50% more efficient than A & 20% more efficient than C. If B can complete a work in 20 days, how many days will A & C together take to compete the same work.
1). \(13\frac{1}{3}\;days\)
2). 14 days
3). 16 days
4). 12 days
1 answers
3 vote
B is 50% more efficient than A
i.e. A : B = 2 : 3
B is 20% more efficient than C
i.e. B : C = 6 : 5
combining both the ratio we get
A : B : C = 4 : 6 : 5
Now, if B can do a work in 20 days, when B = 6
Then, A & C together can do it in $(=\frac{{20 \times 6}}{{4 + 5}} = \frac{{120}}{9})$
$(= 13\frac{1}{3}\;days)$