A shopkeeper sales one transistor for Rs. 910 at a gain of 30% and another for Rs. 940 at a loss of 6%. His total loss or gain per cent is
1). \(7\frac{{11}}{{13}}\%\)
2). \(9\frac{{14}}{{17}}\%\)
3). \(8\frac{{14}}{{17}}\%\)
4). \(10\frac{{11}}{{17}}\%\)
Let,
Cost price of the first transistor = Rs. X
Selling price of first transistor = Rs. 910
And, gain = 30%
? Selling price = Cost price + Gain
∴ 910 = x + 0.30x
⇒ 1.30x = 910
⇒ x = Rs. 700
Again,
Let,
Cost price of the second transistor = Rs. X
Selling price of first transistor = Rs. 940
And, Lost = 6%
? Selling price = Cost price – lost
∴ 940 = x - 0.06x
⇒ 0.94x = 940
⇒ x = Rs. 1000
∴ Total cost price = 700 + 1000 = Rs. 1700
Total selling price = 910 + 940 = Rs. 1850
∴ Gain = 1850 – 1700 = Rs. 150
∴ Gain per cent
= (Gain/Total cost price) × 100
= (150/1700) × 100
= 150/17
$(= 8\frac{{14}}{{17}}\%)$