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A shopkeeper sales one transistor for Rs. 910 at a gain of 30% and another for Rs. 940 at a loss of 6%. His total loss or gain per cent is

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A shopkeeper sales one transistor for Rs. 910 at a gain of 30% and another for Rs. 940 at a loss of 6%. His total loss or gain per cent is
1). \(7\frac{{11}}{{13}}\%\)
2). \(9\frac{{14}}{{17}}\%\)
3). \(8\frac{{14}}{{17}}\%\)
4). \(10\frac{{11}}{{17}}\%\)


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Answered by on | Votes 3 |

Let,

Cost price of the first transistor = Rs. X

Selling price of first transistor = Rs. 910

And, gain = 30%

? Selling price = Cost price + Gain

∴ 910 = x + 0.30x

⇒ 1.30x = 910

⇒ x = Rs. 700

Again,

Let,

Cost price of the second transistor = Rs. X

Selling price of first transistor = Rs. 940

And, Lost = 6%

? Selling price = Cost price – lost

∴ 940 = x - 0.06x

⇒ 0.94x = 940

⇒ x = Rs. 1000

∴ Total cost price = 700 + 1000 = Rs. 1700

Total selling price = 910 + 940 = Rs. 1850

∴ Gain = 1850 – 1700 = Rs. 150

∴ Gain per cent

= (Gain/Total cost price) × 100

= (150/1700) × 100

= 150/17

$(= 8\frac{{14}}{{17}}\%)$

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