In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for both quantities and chose the correct option. Quantity A: A man takes 11/9 times downstream time to row upstream keeping the distance same in both ca

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In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for both quantities and chose the correct option. Quantity A: A man takes 11/9 times downstream time to row upstream keeping the distance same in both ca

Asked on 2019-05-02 12:39:37 by Guest | Votes 0 | Views: 22 | Tags: speed time and distance | mix | Add Bounty

In the following question, two statements are numbered as A and B. On solving these statements we get quantities A and B respectively. Solve for both quantities and chose the correct option.

Quantity A: A man takes 11/9 times downstream time to row upstream keeping the distance same in both cases. What is the speed of boat (m/s) in still water if it takes 6 hours to travel 80 km in downstream?

Quantity B: A boat running in upstream covers 20 km distance in 3 hours while covering the same distance in downstream it takes 2 hours. What is the speed of the boat in still water (m/s)?
1). Quantity A > Quantity B
2). Quantity A < Quantity B
3). Quantity A ≥ Quantity B
4). Quantity A ≤ Quantity B

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Answered by Guest on 2019-05-28 06:20:49 | Votes 3 | #

Solving for Quantity A -

Distance cover = 80 km

Time taken = 6 hours

Speed of downstream = 80/6 = 13.33 kmph

Speed of downstream = Speed of boat + speed of stream ---- (I)

Speed of upstream = speed of boat - speed of stream ---- (II)

Let assume Speed of boat as x kmph ,

Speed of stream as y kmph,

Time taken in upstream is 11/9 times more,

Time taken in upstream = (11/9) × 6 = 7.33 hours

Speed of upstream = 80/7.33 = 10.91 kmph

Substitute the values in Eq (I) and Eq (II);

⇒ x + y = 13.33

⇒ x - y = 10.91

By eliminating y terms in above equation,

⇒ 2x = 24.24

⇒ x = 12.12 kmph

Convert the vale in m/s by multiplying it 18/5,

Speed of boat = 12.12 × (5/18) = 3.36 m/s

Solving for Quantity B -

Let assume speed of boat in still water = x kmph

Speed of stream = y kmph

For the speed of boat in upstream,

Distance covered = 20 km

Time taken = 3 hour

Speed of boat in upstream = 20/3 = 6.67 kmph

For the speed of boat in downstream,

Distance covered = 20 km

Time taken = 2 hour

Speed of boat in downstream = 20/2 = 10 kmph

Speed of downstream = Speed of boat + speed of stream = x + y = 10

Speed of upstream = speed of boat - speed of stream = x - y = 6.67

By eliminating y terms,

⇒ 2x = 16.67

⇒ x = 8.335 kmph

Convert the value in m/s by multiplying 5/18,

⇒ x = 8.335 × (5/18) = 2.315 m/s

∴ Quantity A > Quantity B

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