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Cards numbered from 5 to 55 are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible by 3 but divisible by 7?

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Cards numbered from 5 to 55 are put in a bag. A card is drawn from it at random. Find the probability that the number on the card is not divisible by 3 but divisible by 7?
1). \(\frac{7}{{50}}\)
2). \(\frac{1}{{10}}\)
3). \(\frac{5}{{51}}\)
4). \(\frac{{19}}{{51}}\)


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Answered by on | Votes 0 |

Numbers from 5 to 55 divisible by 7 = {7, 14, 21, 28, 35, 42, 49}

Numbers from 5 to 55, not divisible by 3 but divisible by 7 = {7, 14, 28, 35, 49}

Number of total possible outcomes = 51

∴ Probability = $(\frac{{n\left( {Favourable\;Events} \right)}}{{n\left( {Possible\;outcomes} \right)}}\; = \;\frac{5}{{51}})$

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