In the following question two equations are given in variables x and y. You have to solve these equations and determine relation between x and y. I. 5x2 – 16x + 11 = 0 II. 5y2 – 3y – 2 = 0

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In the following question two equations are given in variables x and y. You have to solve these equations and determine relation between x and y. I. 5x2 – 16x + 11 = 0 II. 5y2 – 3y – 2 = 0

Asked on 2019-05-05 19:36:18 by Guest | Votes 0 | Views: 38 | Tags: algebra | mix | Add Bounty

In the following question two equations are given in variables x and y. You have to solve these equations and determine relation between x and y.

I. 5x² – 16x + 11 = 0

II. 5y² – 3y – 2 = 0
1). x > y
2). x < y
3). x ≥ y
4). x ≤ y

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Answered by Guest on 2019-05-29 05:32:54 | Votes 1 | #

I. 5x² – 16x + 11 = 0

⇒ 5x² – 5x - 11x + 11 = 0

⇒ 5x(x – 1) – 11(x – 1) = 0

⇒ (5x – 11) (x – 1) = 0

Then, x = $(\; + \;\frac{{11}}{5})$ = + 2.2 or x = + 1

II. 5y² – 3y – 2 = 0

⇒ 5y² – 5y + 2y – 2 = 0

⇒ 5y(y - 1) + 2(y - 1) = 0

⇒ (5y + 2)(y – 1) = 0

Then, y =$(\; - \;\frac{2}{5})$ or y = + 1

So, when x = + 2.2, x > y for y = - 0.4 and x > y for y = + 1

And when x = + 1, x > y for y = - 0.4 and x = y for y = + 1

∴ So, we can observe that x ≥ y

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