A sequence of seven consecutive integers is given. The average of the first five integers is 53. The average of all the seven integers is.
Let the first five integers be (a + 1), (a + 2), (a + 3), (a + 4) and (a + 5)
Now,
⇒$ {(a + 1), (a + 2), (a + 3), (a + 4) and (a + 5)} /5 = 53
⇒$ 5a + 15 = 265
⇒$ 5a = 250
⇒$ a = 50
⇒$ Seven consecutive numbers are 51, 52, 53, 54, 55, 56, and 57
∴$ Required average = (51 + 52 + 53 + 54 + 55 + 56 + 57) /7 = 54