A contractor undertook a contract for a construction work to be completed in 180 days. He engaged 120 labours. But only 1/6th of the work was done in 1/5th of the scheduled time. The additional number of labours that will be required to complete the work in time, is
1). 20
2). 40
3). 30
4). 15
Total Scheduled time = 180 days
1/5th of the scheduled time = 180/5 = 36 days
According to the given information,
120 labours can do 1/6th of the total work in 36 days
∴ remaining work = 5/6th of total work
$(\frac{{{M_1}{D_1}}}{{{W_1}}} = \frac{{{M_2}{D_2}}}{{{W_2}}})$
Where, M = Number of men, D = number of days, W = Amount of work
$(\Rightarrow \frac{{120 \times 36}}{{\frac{1}{6}}} = \frac{{{M_2}\; \times 144}}{{\frac{5}{6}}})$
⇒ M2 = 150
∴ Additional Labours required = 150 – 120 = 30