In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer I. 16a2 - 52a + 22 = 0 II. 30b2 + 56b + 10 = 0

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In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer I. 16a2 - 52a + 22 = 0 II. 30b2 + 56b + 10 = 0

Asked on 2019-05-09 00:47:08 by Guest | Votes 0 | Views: 35 | Tags: algebra | numerical ability | Add Bounty

In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer

I. 16a² - 52a + 22 = 0

II. 30b² + 56b + 10 = 0
1). a < b
2). a > b
3). a ≤ b
4). a ≥ b

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Answered by Guest on 2019-06-01 01:21:02 | Votes 0 | #

I. 16a² - 52a + 22 = 0

⇒ 16a² - 8a - 44a + 22 = 0

⇒ 8a(2a - 1) - 22(2a - 1) = 0

⇒ (8a - 22) (2a - 1) = 0

Then, a = 22/8 or a = 1/2

II. 30b² + 56b + 10 = 0

⇒ 30b² + 6b + 50b + 10 = 0

⇒ 6b(5b + 1) + 10(5b + 1) = 0

⇒ (6b + 10) (5b + 1) = 0

Then, b = (-10/6) or b = (-1/5)

So, when a = (22/8), a > b for b = (-10/6) and a > b for b = (-1/5)

And when a = (1/2), a > b for b = (-10/6) and a > b for b = (-1/5)

∴ we can observe that a > b.

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