In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer I. a2 - 61a + 424 = 0 II. b2 + 54b + 53 = 0
In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer
I. a2 - 61a + 424 = 0
II. b2 + 54b + 53 = 01). a < b
2). a > b
3). a ≤ b
4). a ≥ b
1 answers
I. a2 - 61a + 424 = 0
⇒ a2 - 53a - 8a + 424 = 0
⇒ a(a - 53) - 8(a - 53) = 0
⇒ (a - 8) (a - 53) = 0
Then, a = 53 or a = 8
II. b2 + 54b + 53 = 0
⇒ b2 + 53b + b + 53 = 0
⇒ b(b + 53) + 1(b + 53) = 0
⇒ (b + 1) (b + 53) = 0
Then, b = (-53) or b = (-1)
So, when a = (53), a > b for b = (-53) and a > b for b = (-1)
And when a = 8, a > b for b = (-53) and a > b for b = (-1)
∴ we can observe that a > b.Other Questions
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