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25 vote

The H.C.F. of (x2 - 4), (x2 - 5x - 6) and (x2 + x - 6) is - 

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The H.C.F. of (x2 - 4), (x2 - 5x - 6) and (x2 + x - 6) is - 
1). 1
2). (x - 2)
3). (x + 2)
4). (x2 + x - 6)


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1 answers

35 vote
Answered by on | Votes 35 |

x2 - 4 = (x + 2)(x - 2)

x2 - 5x - 6 = x2 - 6x + x - 6

= (x - 6)(x + 1)

x2 + x - 6 = x2 + 3x - 2x - 6

= (x + 3)(x - 2)

Clearly there is no common factor

So H.C.F = 1
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