In the following question two equations are given. You have to solve these equations and determine relation between x and y.
I. 3x2 – 14x + 11 = 0
II. 4y2 + 25y – 21 = 0
I. 3x2 – 14x + 11 = 0
⇒ 3x2 – 3x – 11x + 11 = 0
⇒ 3x(x – 1) - 11(x – 1) = 0
⇒ (x – 1)(3x – 11) = 0
Then, x = + 1 or x = 11/3
II. 4y2 + 25y – 21 = 0
⇒ 4y2 + 28y – 3y – 21 = 0
⇒ 4y(y + 7) – 3(y + 7) = 0
⇒ (4y – 3)(y + 7) = 0
Then, y = + 3/4 or y = - 7
So, when x = + 1, x > y for both y = + ¾ and - 7
And when x = + 11/3, x > y for both y = + ¾ and 7
∴ So, we can observe that x > y.