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In the following question two equations are given. You have to solve these equations and determine relation between x and y. I. 3x2 – 14x + 11 = 0 II. 4y2 + 25y – 21 = 0

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In the following question two equations are given. You have to solve these equations and determine relation between x and y.

I. 3x2 – 14x + 11 = 0

II. 4y2 + 25y – 21 = 0


1). x < y
2). x > y
3). x = y OR relationship cannot be determined
4). x ≥ y


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3 vote
Answered by on | Votes 3 |

I. 3x2 – 14x + 11 = 0

⇒ 3x2 – 3x – 11x + 11 = 0

⇒ 3x(x – 1) - 11(x – 1) = 0

⇒ (x – 1)(3x – 11) = 0

Then, x = + 1 or x = 11/3

II. 4y2 + 25y – 21 = 0

⇒ 4y2 + 28y – 3y – 21 = 0

⇒ 4y(y + 7) – 3(y + 7) = 0

⇒ (4y – 3)(y + 7) = 0

Then, y = + 3/4 or y = - 7

So, when x = + 1, x > y for both y = + ¾ and - 7

And when x = + 11/3, x > y for both y = + ¾ and 7

∴ So, we can observe that x > y.

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