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3 years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is same today. The present age of the baby is

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3 years ago, the average age of a family of 5 members was 17 years. A baby having been born, the average age of the family is same today. The present age of the baby is
1). 1 year
2). \(1\frac{1}{2}\) year
3). 2 years
4). 3 years


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2 vote
Answered by on | Votes 2 |

The average age of a family of 5 members was 17 years.

Sum of their ages = 17 × 5 = 85.

After, 3 years their sum of ages = 85 + 5 × 3 = 100. [?everyone in the family will get older by 3 years.]

The ratio remains same.

Let the age of the baby be ‘x’.

$(\Rightarrow \frac{{100 + x}}{6} = 17)$

⇒ 100 + x = 102

⇒ x = 102 – 100

⇒ x = 2 years.

∴ the present age of the baby = 2 years.

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