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In the following question two equations are given. You have to solve these equations and determine relation between x and y. I. 2x2 + 12x + 18 = 0 II. – 7y2 – 42y – 63 = 0

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In the following question two equations are given. You have to solve these equations and determine relation between x and y.

I. 2x2 + 12x + 18 = 0

II. – 7y2 – 42y – 63 = 0


1). x < y
2). x > y
3). x = y OR relationship cannot be determined
4). x ≥ y


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1 answers

2 vote
Answered by on | Votes 2 |

I. 2x2 + 12x + 18 = 0

⇒ 2x2 + 6x + 6x + 18 = 0

⇒ 2x(x + 3) + 6(x + 3) = 0

⇒ 2(x + 3)(x + 3) = 0

Then, x = - 3

II. – 7y2 – 42y – 63 = 0

⇒ - 7y2 – 21y – 21y – 63 = 0

⇒ - 7y(y + 3) – 21(y + 3) = 0

⇒ - 7(y + 3)(y + 3) = 0

Then, y = - 3

So, x = y = - 3

∴ So, we can observe that x = y.

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