Two equations I and II are given below in each question. You have to solve these equations and give answer
I. x2 + 91 = 20x
II. 10y2 - 29y + 21 = 0x2 + 91 = 20x
(x - 7) (x - 13)
Solving we get, x = 7, 13
10y2 - 29y + 21 = 0
( 5x - 7 ) (2x - 3)
Solving we get, y = 7/5, 3/2
So x is greater than y
So 2 is the correct option