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Two equations I and II are given below in each question. You have to solve these equations and give answer I. x2 + 91 = 20x             II. 10y2 - 29y + 21 = 0

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Two equations I and II are given below in each question. You have to solve these equations and give answer

I. x2 + 91 = 20x            

II. 10y2 - 29y + 21 = 0
1). if x < y
2). if x > y
3). if x ≤ y
4). if x ≥ y


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1 answers

-4 vote
Answered by on | Votes -4 |

x2 + 91 = 20x   

(x - 7) (x - 13)

Solving we get, x = 7, 13

10y2 - 29y + 21 = 0

( 5x - 7 ) (2x - 3)

Solving we get, y = 7/5, 3/2

So x is greater than y

So 2 is the correct option

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