Find two consecutive numbers where thrice the first number is more than twice the second number by 5.
1). 5 and 6
2). 6 and 7
3). 7 and 8
4). 9 and 10
Let two consecutive number be x and x + 1
According to question,
⇒ 3x - 2(x + 1) = 5
⇒ 3x - 2x - 2 = 5
⇒ x = 7
∴ Two numbers are 7 and 8