If the length of the rectangle is increased by 40% and breadth decreases by 50% and this whole process is repeated again then what will be the percentage change in area?
1). 10%
2). 90%
3). 50%
4). 51%
Trick:
If length is increased by 40% and breadth is decreased by 50% then % change would be 30%. Now again the process is repeated and now % change would be 21%. Overall percentage change = 51%
Detailed solution:
Let the initial length and breadth be x and y respectively
Area = xy
Now length is increased by 40% and breadth is decreased by 50%
⇒ New length = x + (40% of x) = (140/100)x
⇒ New breadth = y – (50% of y) = (50/100)y
Now after repeating the same process
⇒ New length = (140/100)x + {40% of (140/100)x}
⇒ (140/100)x + (56/100)x = (196/100)x
⇒ New breadth = (50/100)y – {50% of (50/100)y}
⇒ (50/100)y – (25/100)y = (25/100)y
⇒ New Area = {(196/100)x} × {(25/100)y} = (49/100)xy
∴ Percentage change in area = [{xy – (49/100)xy}/xy] × 100 = 51%