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A load of 200N is lifted by applying an effort of 50N, the mechanical advantage in this case is

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A load of 200N is lifted by applying an effort of 50N, the mechanical advantage in this case is
1). 4
2). 200
3). 1/4
4). 50


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Answered by on | Votes 3 |

Mechanical advantage: This is the ratio of load lifted to effort applied. Thus, if W is the load and P is the corresponding effort, then

Mechanical Advantage $(= \frac{W}{P})$

Mechanical Advantage $(= \frac{{200}}{{50}} = 4)$

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