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What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value) \(80762 \div 2.9997 \times 12 \div (\sqrt {\left( {144 + {{2.01}^4}} \right) \div {{3.18}^2}}) = \:?\)

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What approximate value should come in place of the question mark (?) in the following question? (You are not expected to calculate the exact value)

\(80762 \div 2.9997 \times 12 \div (\sqrt {\left( {144 + {{2.01}^4}} \right) \div {{3.18}^2}}) = \:?\)


1). 161534
2). 40381
3). 40586
4). 50765


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Answered by on | Votes 1 |

$(80762 \div 2.9997 \times 12 \div (\sqrt {\left( {144 + {{2.01}^4}} \right) \div {{3.18}^2}}) = \:?)$

2.9997 = 3

2.01 = 2

3.182 ≈ 3.22 = 10.24 ≈ 10

$(\begin{array}{l} = \frac{{80762}}{3} \times 12 \div \sqrt {\left( {144 + {2^4}} \right) \div 10} \\ = 80762 \times 4 \div \sqrt {\left( {144 + 16} \right) \div 10} \\ = 80762 \times 4 \div \sqrt {160 \div 10} ) \end{array})$

= 80762 × 4 ÷ 4

= 80762

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