Two pipes A and B can fill a tank in 36 hours and 45 hours respectively. If both the pipes are opened simultaneously, how much time will be taken to fill the tank?
Time taken by pipe A to fill a tank = 36 hours
⇒ Part of the tank filled by pipe A in 1 hour = 1/36 ----(1)
Time taken by pipe B to fill a tank = 45 hours
⇒ Part of the tank filled by pipe B in 1 hour = 1/45 ----(2)
Adding equations 1 and 2,
Part of the tank filled by pipe A and B both in 1 hour $(= \frac{1}{{36}} + \frac{1}{{45}} = \frac{{5 + 4}}{{180}} = \frac{9}{{180}} = \frac{1}{{20}})$
∴ Time taken by pipe A and B both to fill the tank completely = 20 hours