A group of men started work and aimed to finish the same in 10 days. After 4 days, 6 men left. The remaining men finished the work in 12 more days. How many men were there in the group initially?
Let, No. of men initially = x
x men can complete the work in 10 days.
∴ Total work = 10x
Work done in 4 days = 4x
∴ Remaining work = 10x – 4x = 6x
According to problem, (x – 6) completed the remaining work in = 12 days
∴ 12(x – 6) = 6x
⇒ 6x = 72
⇒ x = 12
∴ Initially there were 12 men.