In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer.
I. a2 + 4a = 0
II. b2 + 9b + 20 = 0
I. a2 + 4a = 0
⇒ a(a + 4) = 0
Then, a = 0 or a = -4
II. b2 + 9b + 20 = 0
⇒ b2 + 4b + 5b + 20 = 0
⇒ b(b + 4) + 5(b + 4) = 0
⇒ (b + 5)(b + 4) = 0
Then, b = - 5 or b = -4
So, when a = 0, a > b for b = -5 and a > b for b = -4
And when a = -4, a > b for b = -5 and a = b for b = -4
∴ So, we can observe that a ≥ b.