In the given question, two equations numbered l and II are given. You have to solve both the equations and mark the appropriate answer.
I. 12x2 + 5x – 3 = 0
II. 12y2 – 17y + 6 = 0I. 12x2 + 5x – 3 = 0
⇒ 12x2 + 9x – 4x – 3 = 0
⇒ 3x(4x + 3) – 1(4x + 3) = 0
⇒ (4x + 3)(3x – 1) = 0
⇒ x = -3/4, 1/3
II. 12y2 – 17y + 6 = 0
⇒ 12y2 – 8y – 9y + 6 = 0
⇒ 4y(3y – 2) – 3(3y – 2) = 0
⇒ (3y – 2)(4y – 3) = 0
⇒ y = 2/3, 3/4
When x = -3/4, y = 2/3, then x < y
When x = -3/4, y = 3/4, then x < y
When x = 1/3, y = 2/3, then x < y
When x = 1/3, y = 3/4, then x < y
∴ x and y are related as x < y