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If cos A - sin A = 0, and 0° < A < 90° then what is the value of  \(\frac{tan^2 A}{{cos^2 A +sin A}}\)?

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If cos A - sin A = 0, and 0° < A < 90° then what is the value of  \(\frac{tan^2 A}{{cos^2 A +sin A}}\)?
1). 3/√2
2). 2/(1 + √2) 
3). 2√2/(1 + √2) 
4). 2√2


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1 answers

1 vote
Answered by on | Votes 1 |

Given that, 

cos A - sin A = 0

⇒ cos A = sin A

So, A = 45°

$(\frac{tan^2 A}{{cos^2 A + sin A}} )$ = $(\frac{tan^2 45??

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