If cos A - sin A = 0, and 0° < A < 90° then what is the value of \(\frac{tan^2 A}{{cos^2 A +sin A}}\)?
1). 3/√2
2). 2/(1 + √2)
3). 2√2/(1 + √2)
4). 2√2
Given that,
cos A - sin A = 0
⇒ cos A = sin A
So, A = 45°
$(\frac{tan^2 A}{{cos^2 A + sin A}} )$ = $(\frac{tan^2 45??
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7. If sin A - cos A = $\frac{\sqrt{3}-1}{2}$,then the value of sin A . cos A is
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