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If tan A = 1 and tan \(B = \sqrt 3 \) then value of cos (A + B) is

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If tan A = 1 and tan \(B = \sqrt 3 \) then value of cos (A + B) is
1). \(\frac{{1 + \sqrt 3 }}{{2\sqrt 2 }}\)
2). \(\frac{{1 - \sqrt 3 }}{{\sqrt 2 }}\)
3). \(\frac{{1 - \sqrt 3 }}{{2\sqrt 2 }}\)
4). \(\frac{{1 + \sqrt 3 }}{4}\)


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2 vote
Answered by on | Votes 2 |

As known,

⇒ Cos(A + B) = cos A.cos B - sinA .sinB

⇒ tanA = 1 means A = 450

⇒ tan B = $(\sqrt 3 \;means\;B = {60^0})$

⇒ cos (45 + 60) =

 = cos45.cos60 - sin45. sin60

 = (1/√2) × (1/2) - (1/√2) × (√3/2)

 = (1/√2) × (1 - √3)/2

 = (1 - √3)/2√2

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