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If \(x + \frac{1}{x} = - 2\) then the value of \({x^{2n + 1}} + \frac{1}{{{x^{2n + 1}}}}\) where n is a positive integer, is

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If \(x + \frac{1}{x} = - 2\) then the value of \({x^{2n + 1}} + \frac{1}{{{x^{2n + 1}}}}\) where n is a positive integer, is
1). 0
2). 2
3). -2
4). -5


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1 answers

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Answered by on | Votes 0 |

⇒ x + 1/x = -2

When x = -1

Then put,

$(= {\left( { - 1} \right)^{2{\rm{n}}}} \times \left( { - 1} \right) + \frac{1}{{{{\left( { - 1} \right)}^{2{\rm{n}}}} \times \left( { - 1} \right)}})$

= -1 – 1

= -2

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