In what ratio should salt be mixed with soup in order to obtain tasty solution worth Rs. 27 per 150 ml. The cost of soup is Rs. 183 per litre, salt comes for Rs. 30 per kg.
? Cost of 150 ml tasty solution = Rs. 27
∴ Cost of 1 ml tasty solution = Rs. $(\frac{{27}}{{150}})$
∴ Cost of 1 litre of tasty solution = 1000 × (9/50) = Rs. 180
Cost of 1 kg of salt = Cost price of cheaper = c = Rs. 30
Cost of 1 litre of soup = Cost price of dearer = d = Rs. 183
Cost of 1 litre of tasty solution = Mean price = m = Rs. 180
By formula,
$(\begin{array}{l} \frac{{{\rm{Quantity\;of\;salt}}}}{{{\rm{Quantity\;of\;soup}}}} = \frac{{{\rm{Quantity\;of\;Cheaper}}}}{{{\rm{Quantity\;of\;Dearer}}}} = \frac{{{\rm{d}} - {\rm{m}}}}{{{\rm{m}} - {\rm{c}}}}\\ \Rightarrow \frac{{{\rm{Quantity\;of\;Salt}}}}{{{\rm{Quantity\;of\;Soup}}}} = \frac{{183 - 180}}{{180 - 30}} = \frac{3}{{150}} \end{array})$
∴ The required ratio = Salt ? Soup = 1 ? 50.